Quote:
Originally Posted by mcquinn
I was figuring a 2.5 ohm 10 watt resister should drop the voltage on a 510 @ 5volts to 4 volts.The only use I thought of for diodes was to keep electrons from going backwards as in current rctification.I didn't make it far in electronics class too many laws and formulas.
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Alright I checked with some experts on your resistor. A 2.5 ohm resistor would be like trying to run 2 atties, you'd pretty much be cutting your volts/watts in half.
My question. At first I thought a 1 ohm would do it till I dug deeper.
Quote:
If I may ask a couple more questions.
5V and a 2.3 ohm Joye = 10.9W
Now if I added a 1 ohm resister to the mix (in series) would it be:
5V and 3.3 ohms = 7.6W?
And seeing as only 70% of the ohm load is the atty does that mean the atty itself will now be 5.3W?
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In a series circuit you have it right , the voltages and powers divide. 30% to the res. and 70% to the atty 2.3 watts are disapated across the res. and 5.3 across the atty, a .5 ohm res. would be a better solution 8.9 WATTS total , or 18% across the res. for 1.6 watts and 7.3 watts across the atty.
Using the formula: E = Square Root of (P x R). 7.3W is the equivalent of a 2.3 ohm atty at 4.1V.
From looking at the watts the resister is dissipating, 1.6W, a 1 ohm 5W resister would be more than enough.